Determine whether the value given is the roots of the equation or not 2m2 − 5m = 0 ; m = 2, 5 2
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Step-by-step explanation:
Let p(m) = 2m²-5m=0
On Putting m = 2 in eq 1
2m²-5m=0
2(2)² - 5(2) = 0
2×4 -10 = 0
8 -10 = 0
-2 ≠0
Here, m =2 is not the root of p(m).
On Putting m = 5/2 in eq 1.
2m²-5m=0
2(5/2)² - 5(5/2) = 0
2 (25/4) - 25/2 = 0
25/2 - 25/2 = 0
Here, p(5/2) = 0
Hence,p= 2 is not the root of the given equation & p = 5/2 is the root of the Given equation.
Hope it Helps!!
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