Question

Determine whether the values given against each of the Q.E. are the roots
of the equations.
x²-3x-4=0, if x= –1.​

Answer 1

Answer:

Yes, it is root of Q.E x²-3x-4=0, if x= –1.

Step-by-step explanation:

According remainder theorem

G(X= -1)

Therefore P(1) = -1^2 -3(-1) -4

= 1+3-4

= 4-4

= 0

Hence it is Q.E

Answer 2

Quadratic equation

Given quadratic equation = $x^2-3x-4=0$

The value to check for x is -1.

For checking any quadratic equation , that particular is the zeroes of this equation, it is needed to put the value of that zero in equation, if  that value completely satisfies it, then it is the zeroes of that quadratic equation.

On putting $x = -1$ in equation $x^2-3x-4=0$,

$(-1)^2-3(-1)-4=0\\\\\implies 1+3-4=0\\\implies 4-4=0$

Hence, it is verified that -1 is the root of this equation.