Question

Determine whether x = -2/√3
and x = - 3√3
are solutions of given equation or not √3 x square + 11x+6√3=0​

Answer 1

Answer:

let p(x) =√3x^2+11x+6√3

then put the value of con p(x)

p(1)=√3×-2/√3+ 11 × -2√3+ 6√3

=-2-22√3+6√3

=2-16√3

hence p(1) is not a zero of p( x)

p(2)=√3×-3/√3+11×-3/√3+6√3

=-3+(-33/√3)+6√3

=-3-27√3

hence p(2) is not zero of p(x)

therefore-2√3 and -3√3 are not zeroes of p(x)