Question

Determine whether x = - 6 is the root of following quadratic eqn x² +5x – 6 =0​

Answer 1

$\bf\huge\pink{ANSWER}$

• Substituting x = - 6 in
• L. H. S of given equation we get

$\bf{L. H.S = (-6)²+5(-6)– 6 =0}\\ \\=(36) + 5×(-6)-6 \\ \\= (36) + (-30) -6 \\ \\=(36)+(-36) \\ \\ =36-36 \\ \\0 \: \: =R.H.S$

$\bf\red{Therefore}$

• x = - 6 is the root of following quadratic equation x² +5x – 6 =0

Answer 2

Answer:

Centripetal Acceleration

Δvv=Δrr Δ v v = Δ r r or Δv=vrΔr. Δ v = v r Δ r . Figure 4.18 (a) A particle is moving in a circle at a constant speed, with position and velocity vectors at times t and t+Δt. ... The direction of the acceleration vector is toward the center of the circle