Question

determine whether x cube minus x square minus x + 1 has X + 1 has a factor​

Answer 1

Answer:

No

Since the reminder while dividing x^3-x^2-(x+1) by (x+1) is not equal to zero

Answer 2

Step-by-step explanation:

$p(x) = {x}^{3} - {x}^{2} - x + 1$

$g(x) = x + 1$

$x + 1 = 0$

$x = - 1$

$by \: remainder \: theorem$

$p( - 1) = ( - 1) ^{3} - ( - 1)^{2} - ( - 1) + 1$

$= - 1 - 1 + 1 + 1$

$= 0$

$when \: remainder = 0$

$g(x) \: is \: factor \: of \: p(x)$

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