determine which of the following polynomial has X + 1 as a factor x cube -x square - x + 1
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6
Hello !!
X + 1 = 0
X = -1
P( X ) = X³ - X² - X + 1
P ( - 1 ) = (-1)³ - (-1)² - (-1) + 1
=> -1 - 1 + 1 + 1
=> 2 - 2
=> 0
Remainder = 0
So,
( X - 1 ) is a factor of the given polynomial.
X + 1 = 0
X = -1
P( X ) = X³ - X² - X + 1
P ( - 1 ) = (-1)³ - (-1)² - (-1) + 1
=> -1 - 1 + 1 + 1
=> 2 - 2
=> 0
Remainder = 0
So,
( X - 1 ) is a factor of the given polynomial.
manoj4852:
Thanks responding
Answered by
5
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