Math, asked by ammu22229, 4 months ago

determine which of the following polynomials has {x+1}a fator:x^2+x^2+x+1​

Answers

Answered by preenasangeeth
1

Step-by-step explanation:

x+1=0

x=-1

let p(x)=X

 {x }^{2}  + x { }^{2} + x + 1

x=-1 sub in above eqn

(-1)

we get

 {( - 1)}^{2}  + ( - 1) {}^{2}  + ( - 1) + 1 p(x)=1+1-1+1 ( -1,+1 cancelled)

p(x)=2 ( ≠0)

so

x+1 is not a factor of p(x)

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