Question

determine which one has x + 1 as factor
[tex]x^{4} + x^{3} +x^{2} +x+ 1

Answer 1

$\huge \mathfrak {\color{navy}{here \: is \: the \: solution \: for \: your \: question}} \\ \\ p(x) = {x}^{4} + {x}^{3} + {x}^{2} + x + 1 \\ \mathbf \pink{zero \: of \: (x + 1) \: is \: - 1} \\ \mathcal \green{p(x) = 0} \\ {( - 1)}^{4} + {( - 1)}^{3} + {( - 1)}^{2} + ( - 1) + 1 \\ 1 + ( - 1) + 1 + ( - 1) + 1 \\ 3 - 2 \\ 1 \\ \large \mathfrak \red{1\neq \:0 } \\ \large \mathfrak \purple{lhs \neq \: rhs} \\ \huge \mathfrak \pink \therefore \pink {(x + 1) \: is \: not \: a \: factor \: of \: p(x)} \\ \\ \huge \bigstar\color{royalblue}{PLEASE \: \: MARK \: \: ME \: \: AS \: \: } \\ \huge \color{royalblue}{ THE \: \: BRAINLIEST \: \: AND \: \:} \\ \huge \color{royalblue}{FOLLOW} \color{black} \bigstar$