determine x+1 is a factor of p(x) =x³-x² −(2+√2)x+√(2
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sorry I am weak in maths sorry yaar
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Given
Determine x+1 is a factor of p(x) =x³-x² −(2+√2)x+√(2
Solution
Applying remainder theorem, we get
x+1=0
x=−1
Now
x³-x²−(2+ x+)
Replacing x with −1, we get
=(−1)
3
−(−1)
2
−(2+
2
)(−1)+
2
=−1−1+2+
2
+
2
=2
2
Hence, (x+1) is not a factor of polynomial x
3
−x
2
−(2+
2
)x+
2
.
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