Question

determine (x-2) is factor of x³-3x²+4x-4by factor theorem
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Answer 1

Step-by-step explanation:

As we know,

(x-2) = 0

So,

x = 2

Now,

p(2) = 2^3 - 3(2)^2 + 4(2) - 4 = 0

p(2) = 8 - 12 + 8 - 4 = 0

p(2) = 16 - 16 = 0

Since, x=2 is a zero of p(x)

So,

(x-2) is a factor of p(x) = x^3 - 3x^2 + 4x - 4

Answer 2

Answer:

let p(x)=x³-3x²+4x-4

x=2 then

p(2)=2³-3×2²+4×2-4

=8-12+8-4=0

as remainder=0

x-2 is a factor of p(x)...

thanq for allowing me to help u