Question

Determine x³- x²-(3-√3)x+√3 has (x+1) as a factor? ​

Answer 1

Answer:

(x+1) is not a factor of the eq.

Step-by-step explanation:

substitute (-1) in the eq.[according to factor theorem],

p(-1)= (-1)^3-(-1)^2-(3-√3)-1+√3=0

p(-1)= (-1)^3-(-1)^2-(3-√3)-1+√3=0 = (-1) - 1 +3 -√3 +√3=0 [-√3&√3 cancels]

[-√3&√3 cancels] = -2+3

=(-1) not equal to 0

Hope this helps you.....

Answer 2

Step-by-step explanation:

It us the correct answer