Question

determine x³+x²+x+1 has x+1 a factor​

Answer 1

Answer:

Ur answer:

${x}^{3} + {x}^{2} + x + 1 \\ > x + 1 = 0 \\ = > x = - 1 \\ putting \: the \: value \: in \: the \:equation \\ ({ - 1})^{3} + ({ - 1}^{2} ) + ( - 1) + 1 \\ = ( - 1) + 1 - 1 + 1 \\ = 0$

Yes, (x+1) is a factor of x³+x²+x+1.

Step-by-step explanation:

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Answer 2

$let \\ p(x) = {x}^{3} + {x}^{2} + x + 1 \\ putting \: x + 1 =0 \\ \: \: \: x = - 1 \\ \\ so \: now \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ p( - 1) = ({ - 1}^{3}) + ({ - 1}^{2}) + ( - 1) + 1 \\ = - 1 + 1 - 1 + 1 \\ = 0 \\ \\ then \: the \: remainder \: is \: 0 \: so \: x + 1 \: is \: the \: factor \: of \: {x}^{3} + {x}^{2} + x + 1$

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