Question

determine zeeta so that the points p1(2,-3)and p2(zeeta,-8)and p3(12,-21) are the vertices of the fight triangle with right angle at p3.?​

Answer 1

Answer:

p1p3=√[(2-12)^2+(-3+21)^2]

p2 p3=√[zeeta-12)^2+(-8+21)^2]

p1 p2=√[(2-zeeta)^2+(-3+8)^2]

p1 p2^2=p1 p3^2+p2 p3^

substitute in above values of p1p2, p1p3 and p1p2 and simplify

you will get zeeta=35.4