Question

Determine zeroes of polynomial 2x²+7x-4

Answer 1

Hey

Here is your answer,

2x^2+7x -4=0
2x^2+8x -x -4=0
2x(x+4)-1(x+4)=0
(X+4)(2x -1)=0
X+4=0
X=-4
2x-1=0
X=1/2

The zeroes of the polynomial 2x²+7x-4 are -4 , and 1/2.

Hope it helps you!

Answer 2

Answer:

The zeroes of the polynomial are:$\mathrm{x}=\frac{1}{2},-4$

Step-by-step explanation:

Given: $2x^2+7x-4$

We have to determine the zeroes of polynomial$2x^2+7x-4$.

• As we know, Zeroes of Polynomial are the real values of the variable for which the value of the polynomial becomes zero.

We are solving on the following way:

We have,

$2x^2+7x-4$

From the above concept of Zeroes of the Polynomial to finding the zero of$2x^2+7x-4$ is the same as solving the equation$2 x^{2}+7 x-4=0$.

We will split the middle term such that the product of the numbers is the last term and the sum or difference of those numbers is the middle term.

$2x^2+7x-4$

$\begin{array}{l}\Rightarrow 2 \mathrm{x}^{2}+8 \mathrm{x}-\mathrm{x}-4=0 \\\Rightarrow 2 \mathrm{x}(\mathrm{x}+4)-1(\mathrm{x}+4)=0 \\\Rightarrow(2 \mathrm{x}-1)(\mathrm{x}+4)=0 \\\Rightarrow(2 \mathrm{x}-1)=0,(\mathrm{x}+4)=0 \\\end{array}$

Now,

$\Rightarrow 2x-1=0\\2x=1\\x=\frac{1}{2} \\\\\Rightarrow x+4=0\\x=-4$

So,

$\Rightarrow \mathrm{x}=\frac{1}{2},-4$