Question

determined hcf of the following number using Euclid algorithm 52,320

Answer 1

Using Euclid Division Algorithm
320= 52×6 +8
52= 8×6+4
8= 4×2+0
therefore now the remainder becomes zero
HCF of 52 and 320 is 4
Hope this helps you....

Answer 2

heya friend✋✋

here's your answer ⬇⬇

since,320>52

320=52×6+8
52=8×7+4
8=4×2+0


hope it helps u