Question

determined nature of root of quadrilateral equation X^2-15x+54=0​

Answer 1

Answer:

X² - 15X + 54 = 0

=> X² - 9X - 6X + 54 = 0

=> X(X-9) - 6(X-9) = 0

=> (X-6)(X-9) = 0

=> X = 6

AND,

X = 9

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Here a=1 ,b=-15 c =54

b^2-4ac=( -15)^2 -4x1x54

= 225-216

=9

b2 - 4ac is greater than zero.

Therefore,the roots of the quadratic equation are real and unequal.