determinedeterminethe number nearest to 100000but greatest than 10000, which is the exactly divisible by each of 8,15,21
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Step-by-step explanation:
hey there,
taking the LCM of 8 , 15 and 21
LCM (8,15,21)=840
now we will divide divide 100000 by 840
so, we have to compensate 40.
now your requirement is the number which
is greater than 10000.
so, you will get it by 100000+840=100840
hence, 100800 is the number which is divisible
by 8, 15 and 21
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