Math, asked by gausiyaanjum, 7 months ago

determinedeterminethe number nearest to 100000but greatest than 10000, which is the exactly divisible by each of 8,15,21​

Answers

Answered by ramit1196
1

Step-by-step explanation:

hey there,

taking the LCM of 8 , 15 and 21

LCM (8,15,21)=840

now we will divide divide 100000 by 840

so, we have to compensate 40.

now your requirement is the number which

is greater than 10000.

so, you will get it by 100000+840=100840

hence, 100800 is the number which is divisible

by 8, 15 and 21

hope it helps you

please follow me

Similar questions