Question

determining limiting reactant of 3.26g of iron powder added to 80cm3 of 0.200moldm/3 copper (ii) sulphate?

Answer 1

Answer:

3.26 g of iron powder are added to 80.0 cm? of 0.200 mol dm-3 copper(II) sulfate solution. The following reaction occurs: Fe (s) CuSO4 (aq) FeSO4 (aq) Cu (s) Determine the limiting reactant showing your working: Show Your Work Fe (S) Cuso4 Feso4 Cu (s) 3.26 g BOml 0.2 molar Here Cuso4 is the limiting reactant because is more than Fe(s) so it completely reacts Moles 0.2X 800/ 100 0.016 mcles Moles 3.28/55.8 0058

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Answer 2

Fe + CuSO4 = FeSO4 + Cu

1a) Determine the limiting reactant show your working

1b)The mass percentage of copper obtained experimentally was 0.872 g. Calculate the percentage yield of copper