Determining the bending height and total surface area of a cone if its height is 12 cm and diameter is 50.
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Answers
Answered by
1
Step-by-step explanation:
Curved surface area=πrl
=πr
r
2
+h
2
=π×5×
5
2
+12
2
=π×5×13
=65π=204.3cm
2
Answered by
0
R= 25 cm
H= 12 cm
Slant height or bending height = square root of ( 25^2+12^2)
= sr 625+ 144 = sr 769 = 27.71 cm
TSA= pi r ( l+r)
3.14x25(25+ 27.71)
314/100x25(52.71)
314/4(52.71) = 4137.74 sq m
H= 12 cm
Slant height or bending height = square root of ( 25^2+12^2)
= sr 625+ 144 = sr 769 = 27.71 cm
TSA= pi r ( l+r)
3.14x25(25+ 27.71)
314/100x25(52.71)
314/4(52.71) = 4137.74 sq m
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