Question

Deternine number of moles of O in 10.6g NaCO2
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Answer 1

Explanation:

How many moles of oxygen are present in 10.6 g of sodium carbonate?

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We take the quotient mass over molar mass…to find the molar quantity of sodium carbonate salt…

10.6∙g105.99∙g∙mol−1=0.100∙mol .

But we were asked for the molar quantity of OXYGEN atoms, and CLEARLY, each mole of sodium carbonate contains THREE moles of OXYGEN atoms

Answer 2

Answer:

1 mole of Na₂CO₃  = 106 g 

moles in 10.6 g of Na₂CO₃ = 10.6 /106

= 0.1 mole 

106 g contain  atoms of oxygen  = 3 x 6.022 x 10²³

10.6 contain atoms = 0.1 x 3 x 6.022 x 10²³

 = 1.8 x 10²³ atoms