Dev run after Alok who is 200m ahead of him. If speed of Dev is 15 km/hr and that of Alok is 10 km/hr, what will be the distance covered by Dev when he catches Alok? a.650m b.600m c.700m d.750m
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Answer:
Area of remaining park = area of park −4×area of 1 quadrant
=(100)
2
−4×
4
1
×πr
2
=10000−
7
22
×14×14
=10000- 35000
750
2
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