Math, asked by mamtamam76, 24 days ago

devansh covers a distance of 250 km in 5 hours . find the distance covered by him in 6 hours​

Answers

Answered by devapriyasindhu
7

Answer:

Step-by-step explanation:

Distance covered in 5 h =250 km

Distance covered in 1 h = \frac{250}{5} = 50 km

∴ Distance covered in 6 h = 6 × 50 = 300 km

Answered by suraj5070
315

 \sf \bf \huge {\boxed {\mathbb {QUESTION}}}

 \tt Devansh\: covers\: a\: distance\: of\: 250\: km\: in\: 5 hours. \\\tt Find\: the \:distance\: covered\: by\: him\: in\: 6 \:hours.

 \sf \bf \huge {\boxed {\mathbb {ANSWER}}}

 \sf \bf {\boxed {\mathbb {GIVEN}}}

  •  \sf \bf Distance \:coverd\:by \:Devansh\:in\:5\:hours =250\:km

 \sf \bf {\boxed {\mathbb {TO\:FIND}}}

  •  \sf \bf Distance \:covered\:by\:Devansh\:in\:6\:hours

 \sf \bf {\boxed {\mathbb {SOLUTION}}}

 {\pink {\underline {\sf (i) Distance \:covered \:by\:Devansh\:in\:1\:hour}}}

{\mathtt{\green {Let \:the \:distance \:travelled \:by\: Devansh\: in\: 1 \:hour \:be \:y}}}

 \sf \bf \implies y=\dfrac{250}{5}

 \sf \bf \implies y=\dfrac{\cancel{250}}{\cancel{5}}

 \implies{\orange {\boxed {\purple {\sf \bf y=50\:km}}}}

————————————————————————————

 {\pink {\underline {\sf (ii) Distance \:covered \:by\:Devansh\:in\:6\:hours}}}

{\mathtt{\green {Let \:the \:distance \:travelled \:by\: Devansh\: in\: 6 \:hours \:be \:x}}}

 \sf \bf \implies x=6 \times 50

 \implies{\orange {\boxed {\boxed{\purple {\mathfrak{x=300\:km}}}}}}

 {\underbrace {\red {\underline {\red {\overline {\red {\sf \therefore The\:distance \:covered \:by\:Devansh\:in\:6\:hours\:is\:300\:km}}}}}}}

 \sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}

__________________________________________

 \sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}

 \bf Distance \:travelled \:in\:x\:hours = time\times distance \:travelled \:in\:1\:hour

 \bf Distance \:travelled \:in\:1\:hour = \dfrac{distance\:travelled\:in\:given \:time}{given\:time\:taken\:to \:cover\:the \:distance}

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