Computer Science, asked by gouthamchoudhari1911, 3 months ago

Develop a C function to create an array with 10 float elements and create another

module which calculate the mean of float array.

Answers

Answered by ғɪɴɴвαłσℜ
13

\mathtt{\huge{\underline{\red{\bf{C\:function :-}}}}}

#include <stdio.h>

int main()

{

int avg = 0;

int sum =0;

int x=0;

/* Array- declaration – length 3*/

int num[10];

for (x=0; x<10;x++)

{

printf("10 %d \n", (x+1));

scanf("%d", &num[x]);

}

for (x=0; x<10;x++)

{

sum = sum+num[x];

}

for (x=0; x<10;x++)

{

printf("10 %d \n", (x+1));

scanf("%d", &num[x]);

}

for (x=0; x<10;x++)

{

sum = sum+num[x];

}

for (x=0; x<10;x++)

{

printf("10 %d \n", (x+1));

scanf("%d", &num[x]);

}

for (x=0; x<10;x++)

{

sum = sum+num[x];

}

for (x=0; x<10;x++)

{

printf("10 %d \n", (x+1));

scanf("%d", &num[x]);

}

for (x=0; x<10;x++)

{

sum = sum+num[x];

}

for (x=0; x<10;x++)

{

printf("10 %d \n", (x+1));

scanf("%d", &num[x]);

}

for (x=0; x<10;x++)

{

sum = sum+num[x];

}

for (x=0; x<10;x++)

{

printf("10 %d \n", (x+1));

scanf("%d", &num[x]);

}

for (x=0; x<10;x++)

{

sum = sum+num[x];

}

for (x=0; x<10;x++)

{

printf("10 %d \n", (x+1));

scanf("%d", &num[x]);

}

for (x=0; x<10;x++)

{

sum = sum+num[x];

}

for (x=0; x<10;x++)

{

printf("10 %d \n", (x+1));

scanf("%d", &num[x]);

}

for (x=0; x<10;x++)

{

sum = sum+num[x];

}

for (x=0; x<10;x++)

{

printf("10 %d \n", (x+1));

scanf("%d", &num[x]);

}

for (x=0; x<10;x++)

{

sum = sum+num[x];

}

for (x=0; x<10;x++)

{

printf("10 %d \n", (x+1));

scanf("%d", &num[x]);

}

for (x=0; x<10;x++)

{

sum = sum+num[x];

}

avg = sum/10;

printf("Average of entered number is: %d", avg);

return 0;

}

sum = sum+num[x];

}

avg = sum/10;

printf("Average of entered number is: %d", avg);

return 0;

/}

_______________________________________

\mathtt{\huge{\underline{\red{\bf{Result :-}}}}}

Enter number 1

10

Enter number 2

10

Enter number 3

10

Enter number 4

10

Enter number 5

10

Enter number 6

10

Enter number 7

10

Enter number 8

10

Enter number 9

10

Enter number 10

10

Average of entered number is: 10

Note :-

This coding is for 10 unit by changing units we can create n float elements with any of the value .

_______________________________________

Answered by Anonymous
2

Answer:

#include <stdio.h>

int main()

{

int avg = 0;

int sum =0;

int x=0;

/* Array- declaration – length 3*/

int num[10];

for (x=0; x<10;x++)

{

printf("10 %d \n", (x+1));

scanf("%d", &num[x]);

}

for (x=0; x<10;x++)

{

sum = sum+num[x];

}

for (x=0; x<10;x++)

{

printf("10 %d \n", (x+1));

scanf("%d", &num[x]);

}

for (x=0; x<10;x++)

{

sum = sum+num[x];

}

for (x=0; x<10;x++)

{

printf("10 %d \n", (x+1));

scanf("%d", &num[x]);

}

for (x=0; x<10;x++)

{

sum = sum+num[x];

}

for (x=0; x<10;x++)

{

printf("10 %d \n", (x+1));

scanf("%d", &num[x]);

}

for (x=0; x<10;x++)

{

sum = sum+num[x];

}

for (x=0; x<10;x++)

{

printf("10 %d \n", (x+1));

scanf("%d", &num[x]);

}

for (x=0; x<10;x++)

{

sum = sum+num[x];

}

for (x=0; x<10;x++)

{

printf("10 %d \n", (x+1));

scanf("%d", &num[x]);

}

for (x=0; x<10;x++)

{

sum = sum+num[x];

}

for (x=0; x<10;x++)

{

printf("10 %d \n", (x+1));

scanf("%d", &num[x]);

}

for (x=0; x<10;x++)

{

sum = sum+num[x];

}

for (x=0; x<10;x++)

{

printf("10 %d \n", (x+1));

scanf("%d", &num[x]);

}

for (x=0; x<10;x++)

{

sum = sum+num[x];

}

for (x=0; x<10;x++)

{

printf("10 %d \n", (x+1));

scanf("%d", &num[x]);

}

for (x=0; x<10;x++)

{

sum = sum+num[x];

}

for (x=0; x<10;x++)

{

printf("10 %d \n", (x+1));

scanf("%d", &num[x]);

}

for (x=0; x<10;x++)

{

sum = sum+num[x];

}

avg = sum/10;

printf("Average of entered number is: %d", avg);

return 0;

}

sum = sum+num[x];

}

avg = sum/10;

printf("Average of entered number is: %d", avg);

return 0;

/}

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