Question

Deveshi has a total of ₹590 as currency notes in the denominations of ₹50 , ₹20 and ₹10. The ratio of the number of ₹50 notes and ₹20 notes is 3:5. If she has a total of 25 notes, how many notes of each denomination she has?​

Answer 1

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Deveshi has a total of ₹590 as currency notes in the denominations of ₹50 , ₹20 and ₹10. The ratio of the number of ₹50 notes and ₹20 notes is 3:5. If she has a total of 25 notes, how many notes of each denomination she has?

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Let,

The number of ₹50 notes and ₹20 notes be 3x and 5x, respectively.

But she has 25 notes in total.

Therefore, the number of 10 notes = 25 - ( 3x + 5x ) = 25 - 8x

The amount she has

from ₹50 notes: 3x × 50 = Rs 150x

from ₹20 notes: 5x × 20 = Rs 100x

from ₹10 notes: ( 25 - 8x ) × 10 = Rs ( 250 - 80x )

Hence, the total money she has = 150x + 100x + ( 250 - 80x ) = Rs ( 170x + 250 )

But she has Rs 590.

Therefore, 170x + 250 = 590

170x = 590 - 250

170x = 340

x = 340/170

x = 2

The number of ₹50 notes she has = 3x

= 3 × 2 = 6

The number of ₹20 notes she has = 5x

= 5 × 2 = 10

The number of ₹10 notes she has = 25 - 8x

= 25 - ( 8 × 2 )

= 25 - 16 = 9

Answer 2

Step-by-step explanation:

Given:

Devshi has 590 Rupees

₹50, 20 & 10 are there ⇒ Total 25 notes

₹50 & ₹20 ⇒3:5

Notes of ₹50 = 3x

Notes of ₹20 = 5x

Notes of ₹10 = 25 − (3x+5x) = 25 − 8x.

Amount in 50 Rupee notes ⇒50 × 3x= 150x

Amount in 20 Rupee notes ⇒20 × 5x = 100x.

Amount in 10 Rupee notes ⇒10(25−8x) = 250 − 80x

Total Amount =590

⇒150x + 100x + 250 − 80x = 590

⇒250 − 80x = 590 − 250

⇒170x = 340

∴x = 2

So Deveshi has

Notes of ₹50 = 3(2) = 6

i.e., 150(2) = 300Rs.

Notes of ₹20 = 5(2) = 10

i.e., 100(2) = 200Rs.

Notes of ₹10 = 25 − 8(2) = 9

i.e., 9 × 10 =90Rs.