Deveshi has a total of ₹590 as currency notes in the denominations of ₹50 , ₹20 and ₹10. The ratio of the number of ₹50 notes and ₹20 notes is 3:5. If she has a total of 25 notes, how many notes of each denomination she has?
Answers
Answer:
Let
No. of currency notes of Rs 50 = 3x
No. of currency notes of Rs 20 = 5x
No. of currency notes of Rs 10 = 25 - (3x+5x) = 25 - 8x
Amount made by Rs 50 notes = 50 × 3x = 150x
Amount made by Rs 20 notes = 20 × 5x = 100x
Amount made by Rs 10 notes = 10 × (25 - 8x) = 250 - 80x
Total money = 590
⇒ 150x + 100x + 250 - 80x = 590
⇒ 170x = 340
⇒ x = 2
Denominations:
Rs 50 = 3 × 2 = 6
Rs 20 = 5 × 2 = 10
Rs 10 = (25 - 8 × 2) = 9
Step-by-step explanation:
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Step-by-step explanation:
Given Devshi has 590 Rupees
RS50,20&10 are there ⇒ Total 25 notes
Rs50&Rs20 ⇒3:5
Notes of Rs50=3x
Notes of Rs20=5x
Notes of Rs10=25−(3x+5x)=25−8x.
Amount in 50 Rupee notes ⇒50×3x=150x
Amount in 20 Rupee notes ⇒20×5x=100x.
Amount in 10 Rupee notes ⇒10(25−8x)=250−80x
Total Amount =590
⇒150x+100x+250−80x=590
⇒250−80x=590−250
⇒170x=340
∴x=2
So Deveshi has
Notes of Rs.50=3(2)=6i.e;150(2)=300Rs.
Notes of Rs.20=5(2)=10i.e;100(2)=200Rs.
Notes of Rs.10=25−8(2)=9i.e;=90Rs