Question

Deveshi has a total of ₹590 as currency notes in the denominations of ₹50 , ₹20 and ₹10. The ratio of the number of ₹50 notes and ₹20 notes is 3:5. If she has a total of 25 notes, how many notes of each denomination she has?​

Answer 1

Solution :

Let the number of ₹50 notes and ₹20 notes be 3x and 5x, respectively

But she has 25 notes in total.

Therefore, the number of ₹10 notes

➸ 25 - (3x + 5x)

➸ 25 - 8x

The amount she has

from ₹50 notes: 3x x 50 = ₹150x

from ₹20 notes: 5x x 20 = ₹100x

from ₹10 notes: (25 - 8x) x 10 = ₹(250 - 80x)

Hence the total money she has =150x + 100x + (250 - 80x)

➸ ₹(170x +250)

now, 170x + 250 = 590

or 170x = 590 - 250 = 340

➸ x = 340/170

➸ x = 2

The number of ₹50 notes she has

➸ 3x

➸ 3 x 2

➸ 6

The number of ₹20 notes she has

➸ 5x

➸ 5 x 2

➸ 10

The number of ₹10 notes she has

➸ 25 - 8x

➸ 25 - (8 x 2)

➸ 25 - 16

➸ 9

Answer 2

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Given Devshi has 590Ruppes

Rs.50,20 and 10 are there=Total 25notes

Rs .50 And Rs.20=3:5

Notes of Rs.50=3x

Notes of Rs.20=5x

Notes of Rs.10=25-(3x+5x)=25-8x

Amount in 50 Rupee notes=50×3x=150x

Amount in 20 Rupee notes ⇒20×5x=100x.

Amount in 10 Rupee notes ⇒10(25−8x)=250−80x

Total Amount =590

⇒150x+100x+250−80x=590

⇒250−80x=590−250

⇒170x=340

∴x=2

So Deveshi has

Notes of Rs.50=3(2)=6i.e;150(2)=300Rs.

Notes of Rs.20=5(2)=10i.e;100(2)=200Rs.

Notes of Rs.10=25−8(2)=9i.e;=90Rs..

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