Question

Deveshi has a total of ₹590 as currency notes in the denominations of ₹50 , ₹20 and ₹10. The ratio of the number of ₹50 notes and ₹20 notes is 3:5. If she has a total of 25 notes, how many notes of each denomination she has?​

Answer 1

Answer:

Given Devshi has 590 Rupees

RS50,20&10 are there ⇒ Total 25 notes

Rs50&Rs20 ⇒3:5

Notes of Rs50=3x

Notes of Rs20=5x

Notes of Rs10=25−(3x+5x)=25−8x.

Amount in 50 Rupee notes ⇒50×3x=150x

Amount in 20 Rupee notes ⇒20×5x=100x.

Amount in 10 Rupee notes ⇒10(25−8x)=250−80x

Total Amount =590

⇒150x+100x+250−80x=590

⇒250−80x=590−250

⇒170x=340

∴x=2

So Deveshi has

Notes of Rs.50=3(2)=6i.e;150(2)=300Rs.

Notes of Rs.20=5(2)=10i.e;100(2)=200Rs.

Notes of Rs.10=25−8(2)=9i.e;=90Rs

Answer 2

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Deveshi has a total of ₹590 as currency notes in the denominations of ₹50 , ₹20 and ₹10. The ratio of the number of ₹50 notes and ₹20 notes is 3:5. If she has a total of 25 notes, how many notes of each denomination she has?

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Let,

The number of ₹50 notes and ₹20 notes be 3x and 5x, respectively.

But she has 25 notes in total.

Therefore, the number of 10 notes = 25 - ( 3x + 5x ) = 25 - 8x

The amount she has

from ₹50 notes: 3x × 50 = Rs 150x

from ₹20 notes: 5x × 20 = Rs 100x

from ₹10 notes: ( 25 - 8x ) × 10 = Rs ( 250 - 80x )

Hence, the total money she has = 150x + 100x + ( 250 - 80x ) = Rs ( 170x + 250 )

But she has Rs 590.

Therefore, 170x + 250 = 590

170x = 590 - 250

170x = 340

x = 340/170

x = 2

The number of ₹50 notes she has = 3x

= 3 × 2 = 6

The number of ₹20 notes she has = 5x

= 5 × 2 = 10

The number of ₹10 notes she has = 25 - 8x

= 25 - ( 8 × 2 )

= 25 - 16 = 9