Question

Devi bought 7 skirts at Sx each, n skirts at $12 each, (2n+ 1) skirts at $15 each and 4 skirts at $3x each. Find the total cost of the skirts she bought.

7x +12n +15(2n+1)+4(3x)
7x+12x+12n+30n+15
19x+42n+15
​

Answer 1

Answer:

Given:

Devi bought:

7 skirts at $x each,

n skirts at $12 each,

(2n + 1) skirts at $15 each

4 skirts at $3x each

To find:

The total cost of the skirts Devi bought

Solution:

Here we are given the cost of 1 piece of every type of skirts.

So,

We will first find the total cost of each type of skirts bought by Devi separately:

The cost of 7 skirts = \$7x$7x

The cost of n skirts = \$12n$12n

The cost of (2n + 1) skirts = \$15(2n + 1) = \$(30n + 15)$15(2n+1)=$(30n+15)

The cost of 4 skirts = 4 \times \$3x = \$12x4×$3x=$12x

Now, we will add all the cost to get the final answer to the total cost.

∴ The total cost of the skirts is,

= \$ 7x + \$ 12n + \$ (30n + 15) + \$ 12x$7x+$12n+$(30n+15)+$12x

= \$ [7x + 12n + 30n + 15 + 12x]$[7x+12n+30n+15+12x]

= \bold{\$ [19x + 42n + 15]}$[19x+42n+15]

Thus, the total cost of the skirts she bought is \underline{\$ [19x + 42n + 15]}

$[19x+42n+15]

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