Math, asked by khushiraval6781, 7 months ago

devi s mother is three times devi s age . five years ago devi smother was four times as old a devi was then find there present ages

Answers

Answered by seemadas9859
9

Given :

Devi’s mother is three times as old as Devi.

Five years ago, Devi’s mother was four times as old as Devi was then.

To find :

Their present ages =?

Step-by-step explanation :

Let, Devi’s present age be x years.

Then, Devi’s mother present age be 3x years .

Now,

Five years ago Devi’s age = x - 5 years

Five years ago Devi’s mother age = 3x - 5 years

According to the question :

➮ 4 ( x - 5) = 3x - 5

➮ 4x - 20 = 3x - 5

➮ 4x - 3x = 20 - 5

➮ x = 15

Therefore, We get the value of x = 15 years.

Hence,

Devi’s present age, x = 15 years

Devi’s mother present age, 3x = 3 × 15 = 45 year's

Answered by Anonymous
22

To Find:

  • we need to find the present ages of Devi and her mother's age.

Given :

  • Devi's mother is three times Devi's age .

5 years ago

  • Five years ago Devi's mother was four times as old a Devi .

› Let Devi's age be x years .

Then,

› Devi's mother age = 3x

Five years ago

  • Age of Devi = x - 5
  • Age of Devi's mother = 3x - 5

But it's given in the Question that 5 years ago Devi's mother age was four times Devi's age.

So,

Devi's mother age was 4(x - 5)

➔ 3x - 5 = 4(x - 5)

➔ 3x - 5 = 4x - 20

➔ -5 + 20 = 4x - 3x

➔ x = 15

So,

  • Present Age of Devi x = 15 years
  • Present age of Devi's mother 3x = 45 years.

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