Question

device X, when connected to an a.c source has its voltage & current given by

V=230 sin (wt+∏/2) and I= 45sin wt.

1. What is the power dissipation in the circuit? (2)

2. Identify device X. Hence draw the graph showing variation of opposition

offered to current with frequency for this device X.​

Answer 1

Answer:

A device X is connected across an ac source of voltage V=V0sinωt . The current through X is given as I=I0sin(ωt+π2).

1. To find out, we need to be able to calculate the amount of power that the resistor will dissipate. If a current I flows through through a given element in your circuit, losing voltage V in the process, then the power dissipated by that circuit element is the product of that current and voltage: P = I

2.The device is capacitor. The reactance of capacitor is given by Xc = 1/ωC = 1/2πfC (b) Graph of voltage and current w.r. to timeRead more on Sarthaks.com - https://www.sarthaks.com/218309/a-device-x-is-connected-across-an-ac-source-of-voltage-v-v0-sint