Question

devide 18 into three part such they are in A.P and their product is 192

Answer 1

let the three parts be a- d,a,a+d

ACQ,
=>(a- d)+ a+(a+d) =18
=>3a = 18
=>a = 6

Also,
(a- d)(a)(a+d)= 192
=>a(a^2 -d^2 ) = 192
=> 6(36 - d^2)=192. {putting a=6}
=>36 -d^2 =32
=> d^2 = 36-32
=> d^2 =4
=>d=2
so the required no.s are
a- d = 6-2 =4
a =6
a+d = 6+2=8