Question

devide 270 in 3 terms such that product of first and last term is 4896​

Answer 1

Let the three terms of AP be a-d, a, a+d

According to question,

a – d + a + a + d = 207,

3a = 207

a=\frac{207}{3}=69

a = 69

Also, it is given in the question, that, x \times 69=4693

\begin{array}{l}{\Rightarrow x=\frac{4623}{69}} \\ \\{\Rightarrow x=67}\end{array}

Now, d = 69-67 = 2.

Therefore the three terms are:

69-2, 69, 69+2

= 67, 69, 71

Arithmetic progression