Question

Devide 360 into 4 part such that twice of the first part thrice of the second part five times of the third part and six time of the fourth part are all equal

Answer 1

I hope you will be able to understand

Answer 2

Let the parts be x,y,z,a

Since they are all equal we get 2x = 3y = 5z = 6a

Let 2x = 3y = 5z = 6a = K (Constant)

x = k/2, y = k/3, z = k/5, a = k/6

Adding all of them together we get

k/2 + k/3 + k/5 + k/6 = 360

k ( 15+10+6+5) /30 = 360

36k/30 = 360

k = 360*30/36

k = 300

x = 300/2 = 150

y = 300/3 = 100

z = 300/5 = 60

a = 300/6 = 50

x+y+z+a = 150+100+60+50 = 360

hence 4 parts are 150, 100, 60, 50