Question

devide 3x^3+4x^2+5x+18 by x+2 by long divison ​

Answer 1

Answer:

remainder is 0.

quotient is 3x² + 2x + 9

Answer 2

We have to divide 3x³+4x²+5x+18 by x+2 by using

long divison method.

We can divide 3x³+4x²+5x+18 by x+2 by the following way :-

$\begin{gathered}\sf \Large\qquad\qquad 3x^2 -2x + 9\\ \begin{array}{c|c} \cline{2 - 2}\sf x + 2 &\sf 3x^3 + 4x^2 + 5x + 18\\&\sf 3x^3 + 6x^2\ \ \ \ \ \ \ \\ & \sf (-) \ \ (-)\ \ \ \ \ \\ \cline{2-2}& \sf 0 - 2x^2 + 5x \\ &\sf -2x^2 - 4x\\& (+) \ \ (+) \\ \cline{2-2} & \sf 0 + 9x + 18 \ \ \ \ \\& \sf 9x + 18 \ \ \ \ \ \ \\ & \sf( - ) ( - ) \ \ \ \ \ \\ \cline{2-2}&\sf 0 \\ \cline{2-2} \end{array}\\\\ Quotient = 3x^2 - 2x + 9\\\\Remainder = 0\end{gathered}$

Answer :

• quotient = 3x²-2x+9
• remainder = 0