Question

devide 56 in four parts in AP .Such that the ratio of the product of their extremes to the product of their mean is 5:6​

Answer 1

Answer:

Let the four parts be (a – 3d), (a – d), (a + d) and (a + 3d).

Thus, the four parts are a – 3d, a – d, a + d, a + 3d

i.e., 8, 12, 16 and 20.

Hope it will help you.

Answer 2

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Let the four parts be (a – 3d), (a – d), (a + d) and (a + 3d).

Then, sum = 56

⇒ (a – 3d) + (a – d) + (a + d) + (a + 3d) = 56

⇒ 4a = 56

⇒ a = 14

It is given that

Thus, the four parts are a – 3d, a – d, a + d, a + 3d i.e., 8, 12, 16 and 20.