Question

devide Rs 47 between a, b, c so that A may have Rs 10 more than B, and B have Rs 8 more than C

Answer 1

let c=k
b=k+8
a=k+8+10


a+b+c=47
k=7
putting value of k


a=25
b=15
c=7

Answer 2

Total amt= ₹47
Amt a will get = 10+x
Amt b will get = x
Amt c will get = x-8
Solution:
(Amt a will get)+(Amt b will get)+(Amt c will get) = ₹47

= (10+x) + (x) + (x-8) = ₹47
= 10+x+x+x-8 =₹47
= 2+3x =₹47
= 3x = ₹47-2=45
= x = 45/3= ₹15
Now,
Amt a will get = 10+15 = ₹25
Amt b will get = ₹15
Amt c will get = ₹15-8 = ₹7

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