devide the following
2x4+3x2+5x+9 by x-1
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ICSE Class 10
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Sum
Find the remainder (without division) on dividing 3x2 + 5x – 9 by (3x + 2)
SOLUTION
Let 3x + 2 = 0,
then 3x = –2
⇒ x =
-23
Substituting the value of x in f(x)
f(x) = 3x2 + 5x – 9
=
3(-23)2+5(-23)-9
=
3×49-5×23-9
=
43-103-9
=
-63-9
= –2 – 9
= –11
∴ Remainder = –11.
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