Question

devide the following (3x²-2x) +x​

Answer 1

Answer:

Let us first factorize the given polynomial 3x2−2x by finding the HCF of all the terms as follows:

3x2=3×x×x2x=2×x

Therefore, HCF=x

Now, we factor out the HCF from each term of the polynomial 3x2−2x as shown below:

3x2−2x=x(3x−2)

Let us now divide the polynomial 3x2−2x by the monomial x:

x3x2−2x=xx(3x−2)=3x−2

Hence, (3x2−2x)÷x=3x−2.