Question

Devide x³+3x²+3x+1 by x - ½

Answer 1

$\Large{\underline{\underline{\bf{Solution :}}}}$

As, we have to devide (x³ + 3x² + 3x + 1) by x - $\sf{\frac{1}{2}}$

So,

x = $\sf{\frac{1}{2}}$

Put value of x in the polynomial.

$\sf{→(\frac{1}{2})^3 + 3(\frac{1}{2})^2 + 3(\frac{1}{2} + 1} \\ \\ \sf{→\frac{1}{8} + \frac{3}{4} + \frac{3}{2} + 1} \\ \\ \bf{Taking \: LCM} \\ \\ \sf{\frac{1 + 6 + 12 + 8}{8}} \\ \\ \sf{→\frac{27}{8}}$

$\rule{200}{2}$

★ Also refer to the attachment.

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