DF and BE are heights on sides AB and AD respectively of
parallelogram ABCD.
If the area of parallelogram is 1470 sq. cm, AB = 35 cm and
AD = 49 cm, Find the lengths of BE and DF.
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Given:
- DF and BE are heights on sides AB and AD respectively of parallelogram ABCD. If the area of parallelogram is 1470 sq. cm, AB = 35 cm and AD = 49 cm,
To Find:
- Find the lengths of BE and DF.
DIAGRAM : Attached
Required Solution:
Area of parallelogram = 1470 sq.cm
Base = AB
Area = base × altitude
Hence, 1470 = AB × DF
➟ 1470 = 35 × DF
➟ DF = 1470/35 = 42cm
Now, taking AD as the base,
Area = 1470 sq.cm, base = AD = 49cm
Area = base × altitude
➟ 1470 = 49 × BE
➟ BE = 1470/49 = 30cm
- Hence, BE = 30cm and DF = 42cm
Attachments:
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