Question

DF and BE are the height on sides AB and AD respectively in parallelogram ABCD. If the area of the parallelogram is 1470 cm², AB = 35 cm and AD = 49 cm, find the length of BE and DF.

Answer 1

$\textbf{\underline{as you know that}}\\\:\:\:\textbf{area of parallelogram=product of}\\\textbf{base and altitude}$

Here,
length of AD = 49cm
length of AB = 35 cm
area of parallelogram ABCD = 1470 cm²

area of Parallelogram ABCD = length of AD × length of BE = length of AB × length of DF

so, area of ABCD = 1470 = length of AD × length of BE
=> 1470 = 49 × length of BE
length of BE = 1470/49 = 30 cm

similarly, area of ABCD = 1470 = length of AB × length of DF
=> 1470 = 35 × length of DF
length of DF = 1470/35 = 42 cm

hence, BE = 30cm and DF = 42cm

Answer 2

HELLO DEAR,

AD = 49cm
AB = 35 cm

area of parallelogram ABCD = 1470 cm²

we know area of parallelogram = $\bold{base*perpendicular\;\; height}$

Now,

area of Parallelogram ABCD = AD * BE = AB * DF

so, area of ABCD = 1470

1470 = AD * BE

1470 = 49 * BE

BE = 1470/49 = 30 cm

similarly,

area of ABCD = 1470 = AB * DF

1470 = 35 * DF

DF = 1470/35

DF = 42 cm

hence, BE = 30cm and DF = 42cm

I HOPE ITS HELP YOU DEAR,
THANKS