\dfrac c2-3+\dfrac 6d
2
c
−3+
d
6
start fraction, c, divided by, 2, end fraction, minus, 3, plus, start fraction, 6, divided by, d, end fraction when c=14c=14c, equals, 14 and d=3d=3d, equals, 3.
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sorry I didn't understand the question
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