DG and EG are tangent to circle C and circle F. The points of tangency are A, B, D, and E. If m∠DFE = 140°, what is m∠ACB?
A. 160°
B. 140°
C. 120°
D. 110°
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Answered by
11
Final Answer : 140°
Steps:
1) We know that, Sum of angles subtended at the centre and point of contact by tangents down from an external point is supplementary (180°).
=> /GFE + / DGE = 180°
=> 140° + /DGE = 180°
=> /DGE = 40°
3) Again Applying above Theorem,
=> /AGB + / ACB = 180°
=> 40° + /ACB = 180°
=> /ACB = 140° .
Hence, Angle ACB = 140°
Steps:
1) We know that, Sum of angles subtended at the centre and point of contact by tangents down from an external point is supplementary (180°).
=> /GFE + / DGE = 180°
=> 140° + /DGE = 180°
=> /DGE = 40°
3) Again Applying above Theorem,
=> /AGB + / ACB = 180°
=> 40° + /ACB = 180°
=> /ACB = 140° .
Hence, Angle ACB = 140°
Answered by
2
140 is your answer!!!!!
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