Math, asked by kalpeshvalvi99591, 1 day ago

Dhananjay sold his motorcycle to Nilesh at a loss of 28%. Nilesh spend 1680 on its repairs and sold it to Nitin for 35910 making a profit of 12.5% . Find cost of the motorcycle of Dhananjay

Answers

Answered by PushkarAcharya1
2

Answer:

42000

Step-by-step explanation:

let CP be x

then

SP=(100-L%)/100 * CP

SP=(100-28)/100 * x

SP=72/100 * x

SP=0.72x

CP including the cost of repair = 0.72x + 1680

SP of motorcycle = 35910

Profit% = 12.5%

Now

Profit% = Profit/CP * 100

12.5 = SP - CP / CP * 100

12.5 = [35910-(0.72x + 1680)] / 0.72x + 1680 * 100

12.5 = (35910-0.72x-1680)/0.72x + 1680 * 100

12.5/100 = (34230-0.72x)/(0.72x + 1680)

12.5(0.72x + 1680) = 100(34230-0.72x)

9x + 21000 = 3423000-72x

9x + 72x = 3423000 - 21000

81x = 3402000

x = 3402000/81

x = 42000

Therefore CP of motorcycle of Dhananjay is 42000.

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