Question

Dhanesh has equal number of notes of Rs. 50, Rs. 20. Rs. 10 and
Rs. 5. If the total amount is Rs. 1,020, then how many 50 rupee notes
does Dhanesh have ?
(1)
50
(2)
12
(3)
68
(4)
34​

Answer 1

Answer:

12

Step-by-step explanation:

Answer 2

Answer:

Dhanesh has 12 numbers of 50 rupee.

So, option 2 is the correct answer.

Step-by-step explanation:

Given,Dhanesh has equal number of notes of Rs. 50, Rs. 20. Rs. 10 and Rs. 5.

Let each number of notes be x.

So,Total amount

$= 50 \times x + 20 \times x + 10 \times x + 5 \times x \\ = (50 + 20 + 10 + 5) \times x \\ = 85x \: rupees$

It is also given,the total amount is Rs. 1,020

So, according to question,

$85x = 1020 \\ x = \frac{1020}{85} \\ x = \frac{60}{5} \\ x = 12$

So, number of 50 rupees notes are 12.

This is a problem of Algebra.

Some important Algebra formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x - + y)( {x}^{2} - xy + {y}^{2} )$

Know more about Algebra,

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