Question

Dharma invested Rs. P for 3 years in scheme A which offered 12% p.a. simple
interest. She also invested Rs. P + 400 in scheme B which offered 10% compound
interest (compounded annually), for 2 years. If the amount received from scheme
A was less than that received from scheme B, by Rs. 304. what is the value of P?​

Answer 1

Answer:

1st money..

1st money..P=P r = 12 n = 3 year

P r = 12 n = 3 year PRN /100

P r = 12 n = 3 year PRN /100 Px 12 x 3 /100

P r = 12 n = 3 year PRN /100 Px 12 x 3 /100 36 P /100

2nd money

p=p+400 r=10 n=2

p(1+i)ñ

p+400(1+0.1)²

p+400(1.21)

Step-by-step explanation:

about your questions A is less than B

so B-A= 304

p+400(1.21) - 36/100 p = 304

solve it n get ans...