Question

Dheepthi started from point a in south direction. after walking for 4 m she turned to her right and walked 5 m. now she turned to her left and walked 3 m after which she turned to her right. now she walked 4 m and turned to her right again and walked 15 m. now finally she turned to her right and after walking for 7 m, she stopped at point

b. what is the distance ab?

Answer 1

Consider her starting point as origin (0,0)
At the last point she is on (-2,8)
So the distance is,
Distance = √(-2-0)²+(8-0)²
= √ 2² + 8²
= √ 4 + 64
= √ 68
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Answer 2

The distance between a and b is √68 m.

Dheepthi started from point a in south direction. after walking for 4 m, she turned to her right and walked 5 m. now she turned to her left and walked 3 m after which she turned to her right. now she walked 4 m and turned to her right again and walked 15 m. now finally she turned to her right and after walking for 7 m, she stopped at point b.

We have to find the distance ab.

step 1 : Dheepthi started from point a in south direction. after walking for 4 m. line a to x shows it on diagram.

step 2 : After walking for 4 m she turned to her right and walked 5 m. so line x to y shows it on diagram.

step 3 : Now she turned to her left and walked 3 m, so line y to z shows it on diagram.

step 4 : After which she turned to her right. now she walked 4 m, so line z to w shows it on diagram.

step 5 : Now she turned to her right again and walked 15 m, so line w to r shows it on diagram.

step 6 :  finally she turned to her right and after walking for 7 m, she stopped at point b. so the line r to b shows it on diagram.

It is clear in the diagram is distance ab ,

$\sqrt{8^2+2^2}=\sqrt{68}$

Therefore the distance between a and b is √68 m.

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