Question

Dheeraj's salary increased from rupees 5,000 to rupees 6,500 in 2 years. Manoj's salary increased from rupees 4,000 to rupees 5,200 in 1 year 6 months. Which one of them received a greater rate of increment? please help me anyone​

Answer 1

Manoj will get more increment

Rate of increment for Dheeraj's salary $= 15\%$

Rate of increment for Manoj's salary $= 20\%$

Explanation:  

For DHEERAJ

Two years ago Dheeraj's salary was 5000.

Present Dheeraj's salary is 6500.

Increment in two years for Dheeraj $= 6500 - 5000 = 1500$

Increment for one years $= \frac{1500}{2}$ $= 750$

Rate of increment for every years $R_d = \frac{750}{5000}\times 100 = 15\%$

For MANOJ

1 years 6 months ago Manoj's salary was 4000.

Present Manoj's salary is 5200.

Increment in two years for Manoj's is

Increment for one years  $= \dfrac{1200}{\frac{3}{2}} = 800$

Rate of increment for every years $= \frac{800}{4000}\times 100 = 20\%$.

Hence, Manoj will get more increment.

Answer 2

Answer:

Manoj will get more increment

Rate of increment for Dheeraj's salary = 15\%=15%

Rate of increment for Manoj's salary = 20\%=20%

Explanation:

For DHEERAJ

Two years ago Dheeraj's salary was 5000.

Present Dheeraj's salary is 6500.

Increment in two years for Dheeraj = 6500 - 5000 = 1500=6500−5000=1500

Increment for one years = \frac{1500}{2}=

2

1500

= 750=750

Rate of increment for every years R_d = \frac{750}{5000}\times 100 = 15\%R

d

=

5000

750

×100=15%

For MANOJ

1 years 6 months ago Manoj's salary was 4000.

Present Manoj's salary is 5200.

Increment in two years for Manoj's is

Increment for one years = \dfrac{1200}{\frac{3}{2}} = 800=

2

3

1200

=800

Rate of increment for every years = \frac{800}{4000}\times 100 = 20\%=

4000

800

×100=20% .

Hence, Manoj will get more increment.