Math, asked by drashti2224, 10 months ago

Dhwani's age at present is 2 years less then 6 times the age of her son amar. The product of their ages 5 years later will be 330. What is the age of Dhawni when her son was born?​

Answers

Answered by bhagyashreechowdhury
7

The age of Dhawni when her son was born was 23 years.

Step-by-step explanation:

Let the present age of Dhwani be “x” years and her son Amar be “y” years.

It is given that Dhwani’s present age is 2 years less than 6 times her son Amar’s age, so, we have the equation as,

x = 6y – 2  

Now,

After 5 years:

Amar’s age = (y + 5)  years

Dhwani’ age = x + 5 = 6y – 2 + 5 = (6y + 3) years  

According to the question, we get the equation as,

(y+5) * (6y+3) = 330

⇒ 6y² + 3y + 30y + 15 = 330

⇒ 6y² + 33y – 315 = 0

⇒ 2y² + 11y – 105 = 0 ….. [dividing by 3 throughout]

⇒ 2y² + 21y – 10y – 105 = 0

⇒ 2y(y+10.5) – 10(y+10.5) = 0

⇒ (y+10.5)(2y-10) = 0

⇒ y = -10.5 or y = 10/2 = 5

(neglecting the negative value)

y = 5 years Amar’s present age

x = 6*5 – 2 = 30 – 2 = 28 yearsDhwani’s present age  

Thus,  

Dhwani’s age when her son was born will be = 28 – 5 = 23 years

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Answered by ShleshVyas
1

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