Question

Di nitrogen and di hydrogen reacts with each other to prduce ammonia according to reaction

N2(g) +3H2(g) ----- 2NH3(g)

1)calculate the mass of ammonia if 2x10^3g of di nitrogen reacts with 1x10^3g of di hydrogen?

2)will any of the 2 reaction remains unreacted ?

3)if yes,which one and wat would b its mass

Answer 1

(i) Balancing the given chemical equation,

From the equation, 1 mole (28 g) of dinitrogen reacts with 3 mole (6 g) of

dihydrogen to give 2 mole (34 g) of ammonia.

⇒ 2.00 × 103g of dinitrogen will react with dihydrogen i.e.,2.00 × 103g of dinitrogen will react with 428.6 g of dihydrogen.

Given,

Amount of dihydrogen = 1.00 × 103g

Hence, N2 is the limiting reagent.

28 g of N2 produces 34 g of NH3.

Hence, mass of ammonia produced by 2000 g of N2= 2428.57 g

(ii) N2 is the limiting reagent and H2 is the excess reagent. Hence, H2 willremain unreacted.

(iii) Mass of dihydrogen left unreacted = 1.00 × 103g – 428.6 g= 571.4 g